题目描述
给你一个 m 行 n 列的矩阵 matrix ,请按照 顺时针螺旋顺序 ,返回矩阵中的所有元素。
示例 1:

输入:matrix = [[1,2,3],[4,5,6],[7,8,9]] 输出:[1,2,3,6,9,8,7,4,5]
示例 2:

输入:matrix = [[1,2,3,4],[5,6,7,8],[9,10,11,12]] 输出:[1,2,3,4,8,12,11,10,9,5,6,7]
个人C++解答
class Solution {
public:
vector<int> spiralOrder(vector<vector<int>>& matrix) {
int up = 0, down = matrix.size() - 1, left = 0,
right = matrix[0].size() - 1;
vector<int> result;
while (left <= right && up <= down) {
for (int i = left; i <= right; i++)
result.push_back(matrix[up][i]);
up++;
for (int i = up; i <= down; i++)
result.push_back(matrix[i][right]);
right--;
if (up <= down)
for (int i = right; i >= left; i--)
result.push_back(matrix[down][i]);
down--;
if (left <= right)
for (int i = down; i >= up; i--)
result.push_back(matrix[i][left]);
left++;
}
return result;
}
};

