题目描述
给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。
示例 1:

输入:root = [4,2,7,1,3,6,9] 输出:[4,7,2,9,6,3,1]
示例 2:
输入:root = [2,1,3] 输出:[2,3,1]
个人C++解答
GYL
递归不会写 哎 好难
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode() : val(0), left(nullptr), right(nullptr) {}
* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
* };
*/
class Solution {
public:
TreeNode* invertTree(TreeNode* root) {
if(root == nullptr) return root;
TreeNode* Tmp = root->left;
root->left = invertTree(root->right);
root->right = invertTree(Tmp);
return root;
}
};

